SOLVEDWhat volume of 1.00 M NaOH is required to neutralize each of the
What Volume Of 12.0 M Hcl Is Required To. Ml 0.560 ml 21.9 ml 257 ml this problem has been solved! None of the above answered:.
SOLVEDWhat volume of 1.00 M NaOH is required to neutralize each of the
X = 0.25 liters of 250ml. Web what volume of 12.0 m hcl is required to make 75.0 ml of 3.50 m hcl? What volume of 12.0 m hcl is required to make 75.0 ml of 3.50. You'll get a detailed solution from a. 12 m = 12 moles hcl per 1 liter of solution.so 12 moles/ 1 liter = 3 moles/ x liters. Web 75ml=0.075lmolarity=moles/litersmoles=0.075(3.50)=0.2625since the number of moles never changes,we know there are 0.2625moles (or 0.26) in the 12m. = molarity of hcl solution =. Web v₁ = 21.9 ml (following scientific notation, round to the nearest tenths) therefore, the volume of the 12.0 m hcl required is 21.9 ml. The density of your hcl is 1.179. Given, initial molarity of hcl , m1 = 12.0 m final molarity of hcl ,m2 = 3.50 m final volume of hcl… q:
We all know that density = mass/volume. None of the above answered:. Web since you need $\pu{262.5 mmol}$, and the $\pu{12 m }$ solution has $\pu{12 mmol}$ per $\pu{ml}$, then you need $\pu{262.5mmol}\div \pu{12m} = \pu{21.875 ml}$ of $\pu{12 m. The density of your hcl is 1.179. You'll get a detailed solution from a. We all know that density = mass/volume. Mass of hcl in one molar solution which is the molar mass is 36.5. X = 0.25 liters of 250ml. What volume of 12.0 m hcl is required to prepare 16.0 l of 0.250 m hydrochloric acid? 12 m = 12 moles hcl per 1 liter of solution.so 12 moles/ 1 liter = 3 moles/ x liters. Web according to the neutralization law, where, = molarity of concentrated hcl solution = 12.0 m.
